How do you simplify $(csc theta cot theta) / sec theta$ ?

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Answer 1 · 2016-06-30T16:18:39

$(cscthetacottheta)/sectheta=cot^2theta$

As $csctheta=1/sintheta$ , $cottheta=costheta/sintheta$ and $sectheta=1/costheta$

Hence $(cscthetacottheta)/sectheta$

= $((1/sintheta)xx(costheta/sintheta))/(1/costheta$

= $(1/sintheta)xx(costheta/sintheta)xx(costheta/1)$

= $cos^2theta/sin^2theta$

= $cot^2theta$

How do you simplify (csc theta cot theta) / sec theta(csc theta cot theta) / sec theta?