How do you simplify $e^{2 + ln x}$ $e^(2+lnx)$ ?

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Answer 1 · 2015-12-19T18:24:02

$x e^{2}$ $xe^2$

Using laws of exponents together with laws of logs, we get

$e^{2 + ln x} = e^{2} \cdot e^{ln x}$ $e^(2+lnx)=e^2*e^(lnx)$

$= e^{2} \cdot x$ $=e^2*x$

How do you simplify e^(2+lnx)e2+lnxe^(2+lnx)?