How do you simplify $(e^-3 * e^4)/(e^-2 * e^-1)$ ?

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Answer 1 · 2016-03-04T18:03:39

$(e^(-3)*e^4)/(e^(-2)*e^(-1))=e^3$

From laws of exponents, $x^(-n)=1/x^n$ and $x^m*x^n=x^(m+n)$ .

Hence, to convert a negative exponent into a positive one, we may take it to the top or bottom of the fraction.

$therefore(e^(-3)*e^4)/(e^(-2)*e^(-1))=(e^2*e^4*e^1)/(e^4)$

$=e^7/e^4$

$=e^3$

How do you simplify (e^-3 * e^4)/(e^-2 * e^-1)(e^-3 * e^4)/(e^-2 * e^-1)?