How do you simplify $\frac{2}{x + 2} - \frac{3}{2 x - 5}$ $\frac{2}{x+2}-\frac{3}{2x-5}$ ?

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Answer 1 · 2014-10-31T16:12:21

Similar to adding and subtracting fractions, we need to make their denominator similar.

$\frac{2}{x + 2} - \frac{3}{2 x - 5}$ $2/(x + 2) - 3/(2x - 5)$

$\Rightarrow \frac{2 (2 x - 5) - 3 (x + 2)}{(x + 2) (2 x - 5)}$ $=> (2(2x - 5) - 3(x + 2))/((x + 2)(2x - 5))$

$\Rightarrow \frac{4 x - 10 - 3 x - 6}{(x + 2) (2 x - 5)}$ $=> (4x - 10 - 3x - 6)/((x + 2)(2x - 5))$

$\Rightarrow \frac{x - 16}{(x + 2) (2 x - 5)}$ $=> (x - 16)/((x + 2)(2x - 5))$

How do you simplify \frac{2}{x+2}-\frac{3}{2x-5}2x+2−32x−5\frac{2}{x+2}-\frac{3}{2x-5}?