How do you simplify $(\frac { 5x ^ { 3} y ^ { 3} } { 7x ^ { - 4} y } ) ^ { 8}$ ?

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Answer 1 · 2017-01-27T11:40:25

$(5^8x^56y^16)/7^8$

$((5x^3y^3)/(7x^-4y))^8$

$=((5^8x^24y^24)/(7^8x^-32y^8))$

Subtract the indices of like bases to simplify:

$= (5^8 x^(24+32) y^(24-8))/7^8$

$= (5^8x^56y^16)/7^8$

How do you simplify (\frac { 5x ^ { 3} y ^ { 3} } { 7x ^ { - 4} y } ) ^ { 8}(\frac { 5x ^ { 3} y ^ { 3} } { 7x ^ { - 4} y } ) ^ { 8}?