How do you simplify ${(\frac{7 z^{4}}{4})}^{3}$ $(\frac { 7z ^ { 4} } { 4} ) ^ { 3}$ ?

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Answer 1 · 2018-06-20T11:25:45

$\Rightarrow (\frac{343}{64}) z^{12}$ $color(maroon)(=> (343/64) z^12$

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${(a^{m})}^{n} = a^{m n}$ $(a^m)^n = a^(mn)$

${(\frac{7 z^{4}}{4})}^{3}$ $((7z^4)/4)^3$

$\Rightarrow \frac{7^{3} \cdot z^{4 \cdot 3}}{4^{3}}$ $=> (7^3 * z^(4 * 3)) / 4^3$

$\Rightarrow (\frac{343}{64}) z^{12}$ $color(maroon)(=> (343/64) z^12$

How do you simplify (\frac { 7z ^ { 4} } { 4} ) ^ { 3}(7z44)3(\frac { 7z ^ { 4} } { 4} ) ^ { 3}?