How do you simplify i^-11? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer sente Dec 19, 2015 Simplify the expression by using the fact that i^4 = 1 to find i^(-11) = i Explanation: Using that i^2 = -1 and thus i^4 = (i^2)^2 = 1 we have i^-11 = 1/i^11 = i/(i*i^11)= i/i^12 = i/(i^4)^3 = i/1^3 =i/1 = i Answer link Related questions How do I use DeMoivre's theorem to find (1+i)^5? How do I use DeMoivre's theorem to find (1-i)^10? How do I use DeMoivre's theorem to find (2+2i)^6? What is i^2? What is i^3? What is i^4? How do I find the value of a given power of i? How do I find the nth power of a complex number? How do I find the negative power of a complex number? Write the complex number i^17 in standard form? See all questions in Powers of Complex Numbers Impact of this question 7494 views around the world You can reuse this answer Creative Commons License