How do you simplify $i^13$ ?

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Answer 1 · 2016-10-21T18:01:44

$i$

$i=sqrt-1$

$i^2=-1$

$i^3=i$

$i^4=1$

multiplying bi $i$ repeats the pattern.

So any $i^(4n)=i$

Since $13-=1(mod4)$

$i^(13)=i^1=i$

How do you simplify i^13i^13?