How do you simplify i^25? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Konstantinos Michailidis Nov 18, 2015 It is i^25=(i^2)^12*i=(-1)^12*i=i Assuning that i is the imaginary unit with i^2=-1 Answer link Related questions How do I use DeMoivre's theorem to find (1+i)^5? How do I use DeMoivre's theorem to find (1-i)^10? How do I use DeMoivre's theorem to find (2+2i)^6? What is i^2? What is i^3? What is i^4? How do I find the value of a given power of i? How do I find the nth power of a complex number? How do I find the negative power of a complex number? Write the complex number i^17 in standard form? See all questions in Powers of Complex Numbers Impact of this question 39193 views around the world You can reuse this answer Creative Commons License