How do you simplify i^25? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Yonas Yohannes Jan 20, 2016 Breakdown the power to i^25 =( i^24) i =( (-1) ^(1/2) )^(2xx12) i= i Answer link Related questions How do I use DeMoivre's theorem to find (1+i)^5? How do I use DeMoivre's theorem to find (1-i)^10? How do I use DeMoivre's theorem to find (2+2i)^6? What is i^2? What is i^3? What is i^4? How do I find the value of a given power of i? How do I find the nth power of a complex number? How do I find the negative power of a complex number? Write the complex number i^17 in standard form? See all questions in Powers of Complex Numbers Impact of this question 3329 views around the world You can reuse this answer Creative Commons License