How do you simplify i^28?

1 Answer
Mar 20, 2016

i^28 = 1

Explanation:

We will use the following:

  • i^4 = i*i*i*i = i^2*i^2 = -1*-1 = 1
  • a^(bc) = (a^b)^c

With these, we have

i^28 = i^(4*7) = (i^4)^7 = 1^7 = 1