How do you simplify $i^{37}$ $i^37$ ?

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Answer 1 · 2016-02-19T05:07:44

It is $i$ $i$

Remember that $i^{2} = - 1$ $i^2=-1$ hence

$i^{37} = (i^{36}) \cdot i = {(i^{2})}^{18} \cdot i = {(- 1)}^{18} \cdot i = i$ $i^37=(i^36)*i=(i^2)^18*i=(-1)^18*i=i$

How do you simplify i^37i37i^37?