How do you simplify i^922i922?

1 Answer
Nov 21, 2015

i^922 = -1i922=1

Explanation:

If m, n in NN then:

a^(m+n) = stackrel "m+n times" overbrace ((a)(a)...(a)) = stackrel "m times" overbrace ((a)(a)...(a)) stackrel "n times" overbrace ((a)(a)...(a)) = a^m*a^n

Hence if m, n in NN then:

(a^m)^n = stackrel "n times" overbrace ((a^m)(a^m)...(a^m)) = a^(stackrel "n times" overbrace (m+m+...+m)) = a^(mn)

So:

i^922 = i^(2*461) = (i^2)^461 = -1^(461) = (-1)^(2*230)(-1)^1

= ((-1)^2)^230(-1) = 1^230(-1) = -1