How do you simplify #ln(1/2) - ln(1) #? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Trevor Ryan. Feb 9, 2016 #-ln2# Explanation: From laws of logs, #ln(a/b)=lna-lnb# and #ln(1)=0# since #e^0=1#. Therefore #ln(1/2)-ln(1)=(ln1-ln2)-ln1# #=0-ln2-0# #=-ln2# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 24638 views around the world You can reuse this answer Creative Commons License