How do you simplify $ln \sqrt{e^{2} + 1} - \frac{1}{2} ln (1 + \frac{1}{e^{2}})$ $ln sqrt(e^2 + 1) - 1/2 ln (1+ 1/e^2)$ ?

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How do you simplify $ln \sqrt{e^{2} + 1} - \frac{1}{2} ln (1 + \frac{1}{e^{2}})$ $ln sqrt(e^2 + 1) - 1/2 ln (1+ 1/e^2)$ ?

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Answer 1 · 2016-09-18T23:05:56

$1$ $1$

Explanation:

$ln \sqrt{e^{2} + 1} - \frac{1}{2} ln (1 + \frac{1}{e^{2}}) = \frac{1}{2} ln (e^{2} + 1) - \frac{1}{2} (ln (e^{2} + 1) - 2)$ $ln sqrt(e^2 + 1) - 1/2 ln (1+ 1/e^2)=1/2 ln(e^2+1)-1/2(ln(e^2+1)-2)$
$= 1$ $=1$

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How do you simplify $ln \sqrt{e^{2} + 1} - \frac{1}{2} ln (1 + \frac{1}{e^{2}})$ $ln sqrt(e^2 + 1) - 1/2 ln (1+ 1/e^2)$ ?

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How do you simplify $ln \sqrt{e^{2} + 1} - \frac{1}{2} ln (1 + \frac{1}{e^{2}})$ $ln sqrt(e^2 + 1) - 1/2 ln (1+ 1/e^2)$ ?