How do you simplify $root3(125x^3y^6z^9)$ ?

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Answer 1 · 2016-10-27T03:09:41

$5xy^2z^3$

$root(3)(125x^3y^6z^9)$
$=(5^3x^3y^6z^9)^(1/3)$
$=(5^(3*1/3))(x^(3*1/3))(y^(6*1/3))(z^(9*1/3))$
$=5xy^2z^3$

How do you simplify root3(125x^3y^6z^9)root3(125x^3y^6z^9)?