How do you simplify $\sqrt[3]{128 x^{6}}$ $root3(128x^6)$ ?

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Answer 1 · 2015-09-27T09:00:21

$4 x^{2} \cdot 2^{\frac{1}{3}}$ $4x^2 *2^(1/3)$

Written in exponent form it is ${(128 x^{6})}^{\frac{1}{3}}$ $(128x^6)^(1/3)$

= ${(2^{7} x^{6})}^{\frac{1}{3}}$ $(2^7 x^6)^(1/3)$

= $2^{\frac{6}{3}} \cdot 2^{\frac{1}{3}} \cdot x^{\frac{6}{3}}$ $2^(6/3)*2^(1/3) *x^(6/3)$

= $2^{2} \cdot 2^{\frac{1}{3}} \cdot x^{2}$ $2^2 *2^(1/3) *x^2$

= $4 x^{2} \cdot 2^{\frac{1}{3}}$ $4x^2 *2^(1/3)$

How do you simplify root3(128x^6)3√128x6root3(128x^6)?