Question

How do you simplify `root3(16a^3b^4c^5 )`?

Answer 1

#2^(4/3).a.b^(4/3).c^(5/3)#

Explanation:

Given, `root(3)[16a^3b^4c^5]`
`rArr [2^4a^3b^4c^5]^(1/3)` [ as `(a^M)^N=a^(MN)`]
`rArr2^(4xx1/3).a^(3xx1/3).b^(4xx1/3.c^(5xx1/3)`
#rArr 2^(4/3).a.b^(4/3).c^(5/3)#