How do you simplify $\sqrt[3]{54 x} - \sqrt[3]{2 x^{4}}$ $root3(54x)-root3(2x^4)$ ?

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Answer 1 · 2016-09-01T13:40:07

$(3 - x) \sqrt[3]{2 x}$ $(3-x)root(3)(2x)$

you can substitute 54 by the product of its factors $2 \cdot 3^{3}$ $2*3^3$ and have the equivalent expression:

$\sqrt[3]{2 \cdot 3^{3} x} - \sqrt[3]{2 x^{3} \cdot x}$ $root(3)(2*3^3x)-root(3)(2x^3*x)$

you can partially simplify:

$\sqrt[3]{2 x} \cdot (\sqrt[3]{3^{3}}) - \sqrt[3]{2 x} \cdot \sqrt[3]{x^{3}}$ $root(3)(2x)*(root(3)(3^3))-root(3)(2x)*root(3)(x^3)$

$3 \sqrt[3]{2 x} - x \sqrt[3]{2 x}$ $3root(3)(2x)-xroot(3)(2x)$

$(3 - x) \sqrt[3]{2 x}$ $(3-x)root(3)(2x)$

How do you simplify root3(54x)-root3(2x^4)3√54x−3√2x4root3(54x)-root3(2x^4)?