How do you simplify root3(81x^8 y^12)?

1 Answer

3^(4/3) x^(8/3) y^4=3x^2y^4root(3)(3x^2)

Explanation:

With the expression root(3)(81x^8y^12), we're taking the cube root of all the terms. We can write the cube root as a power of 1/3, and so we get:

(81 x^8 y^12)^(1/3)

We can now distribute the 1/3 exponent to all the individual terms:

81^(1/3) xx (x^8)^(1/3) xx (y^12)^(1/3)

I'm going to express 81=3^4 and will also use the rule that (x^a)^b=x^(ab):

3^(4xx(1/3)) xx x^(8xx(1/3)) xx y^(12xx(1/3))

which we can simplify:

3^(4/3) xx x^(8/3) xx y^(12/3)

3^(4/3) xx x^(8/3) xx y^4

We can now take the fractional exponents and where there is even divisibility, that lies outside of the root. Where there is a remainder, that can stay as a fraction or be shown under a root sign:

3^(3/3) xx 3^(1/3) xx x^(6/3) xx x^(2/3) xx y^4

3x^2y^4 3^(1/3)x^(2/3)=3x^2y^4root(3)(3x^2)