How do you simplify $\sqrt[3]{8 g^{6}}$ $root3(8g^6)$ ?

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Answer 1 · 2015-11-15T11:36:15

$\sqrt[3]{2^{3} g^{3} g^{3}} = 2 g^{2}$ $root(3)(2^3 g^3 g^3) = 2 g^2$

Given: $\sqrt[3]{8 g^{6}}$ $root(3)(8g^6$

$2^{3} = 8$ $2^3 =8$
$g^{6} = g^{3 + 3} = g^{3} g^{3}$ $g^6= g^(3+3) = g^3 g^3$

$\sqrt[3]{2^{3} g^{3} g^{3}} = 2 g g = 2 g^{2}$ $root(3)(2^3 g^3 g^3) = 2 gg = 2g^2$

How do you simplify root3(8g^6)3√8g6root3(8g^6)?