How do you simplify $root4(2401x^9y^14)$ ?

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Answer 1 · 2016-11-13T20:08:05

$=7x^2y^3root4(xy^2)$

Write the term as the product of its prime factors ... group in multiples of 4 if possible,

$root4 (2401x^9y^14$

$=root4(7^4 *x^8*x*y^12*y^2" "larr$ divide the indices by the root

$=7x^2y^3root4(xy^2)$

How do you simplify root4(2401x^9y^14)root4(2401x^9y^14)?