How do you simplify $root4(32x^4 y^5 n^10)$ ?

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Answer 1 · 2016-07-09T08:41:54

$root(4)(32x^4y^5n^10)=2xyn^2root(4)(2yn^2)$

$root(4)(32x^4y^5n^10)$

= $root(4)(2×2×2×2×2×x×x×x×x×y×y×y×y×y×n×n×n×n×n×n×n×n×n×n)$

= $root(4)(ul(2×2×2×2)×2×ul(x×x×x×x)×ul(y×y×y×y)×y×ul(n×n×n×n)×ul(n×n×n×n)×n×n)$

= $2x×y×n×n×root(4)(2y×n×n)$

= $2xyn^2root(4)(2yn^2)$

How do you simplify root4(32x^4 y^5 n^10)root4(32x^4 y^5 n^10)?