How do you simplify $root4(80)$ ?

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Answer 1 · 2016-06-16T22:02:04

$= 2sqrt5$

It helps to write a number as the product of its prime factors first.
$80 = 2xx2xx2xx2xx5$

$80 = 2^4 xx 5$

At least we can find the 4th root of part of it and then leave the rest as a radical.

$root(4)80 = root(4)(2^4 xx 5)$

$= 2sqrt5$

How do you simplify root4(80)root4(80)?