How do you simplify $sin^-1(sin (1/6)(pi))$ ?

Question

2198 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-12T12:38:02

$pi/6$ .

$sin and sin^(-1)$ are each inverse of the other.

So, applied in succession, both $sin sin^(-1) and sin^(-1) sin$ return the operand.

$sin sin^(-1) x = x and sin sin^(-1) y = y$

How do you simplify sin^-1(sin (1/6)(pi))sin^-1(sin (1/6)(pi))?