How do you simplify ${sin}^{- 1} (x) + {cos}^{- 1} (x) = \frac{π}{2}$ $sin^-1(x)+cos^-1(x)=pi/2$ ?

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Answer 1 · 2016-06-03T04:34:18

$x = \frac{π}{4}$ $x = pi/4$

You can write;
$x + x = \frac{π}{2}$ $x + x = pi/2$ --> $2 x = \frac{π}{2}$ $2x = pi/2$ --> $x = \frac{π}{4}$ $x = pi/4$

How do you simplify sin^-1(x)+cos^-1(x)=pi/2sin−1(x)+cos−1(x)=π2sin^-1(x)+cos^-1(x)=pi/2?