How do you simplify $\frac{{sin}^{2} x + 2 sin x + 1}{sin x + 1}$ $(sin^2x+2sinx+1)/(sinx+1)$ ?

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How do you simplify $\frac{{sin}^{2} x + 2 sin x + 1}{sin x + 1}$ $(sin^2x+2sinx+1)/(sinx+1)$ ?

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Answer 1 · 2016-09-19T09:31:09

$sin x + 1$ $sin x +1$

Explanation:

$\frac{{sin}^{2} x + 2 sin x + 1}{sin x + 1} = \frac{{(sin x + 1)}^{2}}{sin x + 1} = sin x + 1$ $(sin^2x+2sinx+1)/(sinx+1)=(sinx+1)^2/(sinx + 1) = sin x +1$

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How do you simplify $\frac{{sin}^{2} x + 2 sin x + 1}{sin x + 1}$ $(sin^2x+2sinx+1)/(sinx+1)$ ?

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Explanation:

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How do you simplify (sin^2x+2sinx+1)/(sinx+1)sin2x+2sinx+1sinx+1(sin^2x+2sinx+1)/(sinx+1)?

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How do you simplify $\frac{{sin}^{2} x + 2 sin x + 1}{sin x + 1}$ $(sin^2x+2sinx+1)/(sinx+1)$ ?