How do you simplify $\frac{({sin}^{4} (x) - {sin}^{2} (x))}{sec x}$ $((sin^4(x)-sin^2(x)))/secx$ ?

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How do you simplify $\frac{({sin}^{4} (x) - {sin}^{2} (x))}{sec x}$ $((sin^4(x)-sin^2(x)))/secx$ ?

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Answer 1 · 2015-06-30T01:14:04

Simplify f(x)

Explanation:

$f (x) = ({sin}^{2} x) ({sin}^{2} x - 1) cos x = ({sin}^{2} x) (- {cos}^{2} x) . cos x$ $f(x) = (sin^2 x)(sin^2 x - 1) cos x = (sin^2 x) (- cos^2 x).cos x$ =

$= - \frac{1}{4} cos x . {sin}^{2} 2 x$ $= - 1/4 cos x.sin^2 2x$

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How do you simplify $\frac{({sin}^{4} (x) - {sin}^{2} (x))}{sec x}$ $((sin^4(x)-sin^2(x)))/secx$ ?

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How do you simplify ((sin^4(x)-sin^2(x)))/secx(sin4(x)−sin2(x))secx((sin^4(x)-sin^2(x)))/secx?

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How do you simplify $\frac{({sin}^{4} (x) - {sin}^{2} (x))}{sec x}$ $((sin^4(x)-sin^2(x)))/secx$ ?