Question

How do you simplify, `sin(theta)+cos(theta)tan(theta)`?

Answer 1

Just use the fact that `tan(theta)=sin(theta)/cos(theta)` to write `sin(theta)+cos(theta)tan(theta)=sin(theta)+cos(theta)\cdot sin(theta)/cos(theta)` and then cancel the `cos(theta)`'s to say `sin(theta)+cos(theta)tan(theta)=2sin(theta)`.