How do you simplify $sin(x) tan (x) + cos (x)$ ?

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Answer 1 · 2016-03-26T16:58:41

$sin(x)tan(x)+cos(x)=sec(x)$

$sin(x)tan(x)+cos(x) = sin(x)sin(x)/cos(x)+cos(x)$

$=sin^2(x)/cos(x)+cos(x)$

$=sin^2(x)/cos(x)+cos^2(x)/cos(x)$

$=(sin^2(x)+cos^2(x))/cos(x)$

$=1/cos(x)$

$=sec(x)$

Answer 2 · 2016-06-13T07:02:12

$secx$

Given

$sinxtanx+cosx$

$=cosx((sinx)/(cosx)*tanx+1)$

$=cosx(tanx*tanx+1)$
$=cosx(tan^2x+1)$
$=cosx*sec^2x$
$(" putting "(tan^2x+1)=sec^2x)$
$=secx" (putting" cosx*secx=1)$

How do you simplify sin(x) tan (x) + cos (x)sin(x) tan (x) + cos (x)?