How do you simplify $\frac{sin 2 x}{{cos}^{2} x - {sin}^{2} x}$ $(sin2x)/(cos^2x-sin^2x)$ ?

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Answer 1 · 2015-07-17T00:44:08

Simplify: $\frac{sin 2 x}{{cos}^{2} x - {sin}^{2} x}$ $(sin 2x)/(cos^2 x - sin^2 x)$ = tan 2x

Reminder: $cos 2 x = {cos}^{2} x - {sin}^{2} x$ $cos 2x = cos^2 x - sin^2 x$

$\frac{sin 2 x}{{cos}^{2} x - {sin}^{2} x} = \frac{sin 2 x}{cos 2 x} = tan 2 x$ $(sin 2x)/(cos^2 x - sin^2 x) = (sin 2x)/(cos 2x) = tan 2x$

How do you simplify (sin2x)/(cos^2x-sin^2x)sin2xcos2x−sin2x(sin2x)/(cos^2x-sin^2x)?