Question

How do you simplify `sinxsecx`?

Answer 1

`sin(x)sec(x)=tan(x)`

Explanation:

`sec(x)=1/cos(x)`

and

`tan(x)=sin(x)/cos(x)`

so

`sin(x)sec(x)=sin(x)(1/(cos(x)))=sin(x)/cos(x)=tan(x)`