How do you simplify $\sqrt{- 100 a^{4} b^{2}}$ $sqrt(-100a^4b^2)$ ?

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Answer 1 · 2016-11-16T01:52:12

$10 i a^{2} b$ $10i a^2 b$

If you are simplifying, the answer is just positive, not positive and negative.

$\sqrt{- 100 a^{4} b^{2}}$ $sqrt(-100a^4b^2)$

$\sqrt{- 1}$ $sqrt(-1)$ = $i$ $i$ , $\sqrt{100} = 10$ $sqrt(100)=10$ , $\sqrt{a^{4}} = a^{2}$ $sqrt(a^4)=a^2$ , $\sqrt{b^{2}} = b$ $sqrt(b^2)=b$

$(i \cdot 10 \cdot a^{2} \cdot b) = 10 i a^{2} b$ $(i*10*a^2*b)=10i a^2 b$

How do you simplify √−100a4b2sqrt(-100a^4b^2)?