How do you simplify sqrt(108x^6y^4z^5)? Prealgebra Exponents, Radicals and Scientific Notation Square Root 1 Answer Shwetank Mauria May 29, 2017 sqrt(108x^6y^4z^5)=6x^3y^2z^2sqrt(3z) Explanation: sqrt(108x^6y^4z^5) = sqrt(2xx2xx3xx3xx3xx x xx x xx x xx x xx x xx x xxyxxyxxyxxyxxzxxzxxzxxzxxz) = sqrt(ul(2xx2)xxul(3xx3)xx3xx ul(x xx x) xx ul(x xx x) xx ul(x xx x) xxul(yxxy)xxul(yxxy)xxul(zxxz)xxul(zxxz)xxz) = 2xx3xx x xx x xx x xxyxxyxxzxxz xxsqrt(3xxz) = 6x^3y^2z^2sqrt(3z) Answer link Related questions How do you simplify (2sqrt2 + 2sqrt24) * sqrt3? How do you simplify sqrt735/sqrt5? How do you rationalize the denominator and simplify 1/sqrt11? How do you multiply sqrt[27b] * sqrt[3b^2L]? How do you simplify 7sqrt3 + 8sqrt3 - 2sqrt2? How do you simplify sqrt468 ? How do you simplify sqrt(48x^3) / sqrt(3xy^2)? How do you simplify sqrt ((4a^3 )/( 27b^3))? How do you simplify sqrt140? How do you simplify sqrt216? See all questions in Square Root Impact of this question 2818 views around the world You can reuse this answer Creative Commons License