How do you simplify $sqrt(121x^10)$ ?

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Answer 1 · 2015-11-07T12:57:39

$sqrt(121x^10) = 11abs(x)^5$

If $a >= 0$ then $sqrt(a^2) = a$

For any $a in RR$ , $(-a)^2 = a^2$

Hence: $sqrt(a^2) = abs(a)$ for all $a in RR$

So:

$sqrt(121x^10) = sqrt((11x^5)^2) = abs(11x^5) = 11abs(x)^5$

How do you simplify sqrt(121x^10)sqrt(121x^10)?