How do you simplify $\sqrt{125 j^{12}}$ $sqrt(125j^12)$ ?

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Answer 1 · 2017-01-26T17:17:17

$= 5 j^{6} \sqrt{5}$ $=5j^6 sqrt5$

It is helpful when finding roots, to write the number under the root as the product of its prime factors.

$\sqrt{125 j^{12}} = \sqrt{5 \times 5 \times 5 \times j^{12}}$ $sqrt(125j^12) = sqrt(5xx5xx5xx j^12$

$= \sqrt{5 \times 5^{2} j^{12}}$ $=sqrt(5xx5^2 j^12)$

Find the roots where possible:

$= 5 j^{6} \sqrt{5}$ $=5j^6 sqrt5$

(For indices- divide the index by the root)

How do you simplify √125j12sqrt(125j^12)?