How do you simplify $\sqrt{\frac{2}{75}}$ $sqrt(2 / 75)$ ?

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Answer 1 · 2018-03-30T00:37:18

$\Rightarrow \frac{1}{5} \sqrt{\frac{2}{3}}$ $=>1/5sqrt(2/3)$

$\Rightarrow \sqrt{\frac{2}{75}}$ $=>sqrt(2/75)$

$\Rightarrow \sqrt{\frac{2}{3 \cdot 25}}$ $=>sqrt(2/(3*25)$

$\Rightarrow \sqrt{\frac{2}{3 \cdot 5^{2}}}$ $=>sqrt(2/(3*5^2)$

$\Rightarrow \frac{1}{5} \sqrt{\frac{2}{3}}$ $=>1/5sqrt(2/3)$

Answer 2 · 2018-03-30T00:43:45

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1) Rewrite problem
2)Take the biggest perfect square out of the bottom square root
3) Rationalize denominator

Answer 3 · 2018-03-30T13:55:51

$\frac{\sqrt{6}}{15}$ $sqrt 6/15$

$\sqrt{\frac{2}{75}}$ $sqrt(2/75)$

$:.=sqrt2/sqrt 75xxsqrt 75/sqrt 75$

$:.=sqrt(2*75)/75$

$:.=sqrt150/75$

$:.=sqrt (2*3*5*5)/75$

$:.sqrt5*sqrt5=5$

$:.=(cancel5^1 sqrt 6)/cancel75^15$

$:.=sqrt6/15$

How do you simplify sqrt(2 / 75)√275sqrt(2 / 75)?