How do you simplify $sqrt(24 x^10 y^11)$ ?

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Answer 1 · 2016-08-19T15:58:34

$2x^5y^5sqrt(6y)$

Note that $24" " =" " 4xx6" "=" " 2^2xx6$ giving:

$sqrt(2^2xx6x^10y^11)$

take the $2^2$ outside the square root.

$2sqrt(6x^10y^11)$

Note that $sqrt(x^10)" "=sqrt(x^2xx x^2 xx x^2xx x^2xx x^2)=x^5$

Take all of the $x^2$ outside the square root.

$2x^5sqrt(6y^11)$

Note that $sqrt(y^11)" " =" " sqrt((y^2)^5xxy)" " =" " y^5sqrt(y)$

$2x^5y^5sqrt(6y)$

How do you simplify sqrt(24 x^10 y^11)sqrt(24 x^10 y^11)?