How do you simplify $\sqrt{\frac{27}{4}}$ $sqrt(27/4)$ ?

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Answer 1 · 2015-07-13T20:10:03

Try factoring the components.

$27 = 3 \cdot 3 \cdot 3 and 4 = 2 \cdot 2$ $27=3*3*3and 4=2*2$

Let's rewrite an regroup:

$= \sqrt{\frac{3 \cdot 3 \cdot 3}{2 \cdot 2}} = \frac{\sqrt{3 \cdot 3 \cdot 3}}{\sqrt{2 \cdot 2}}$ $=sqrt((3*3*3)/(2*2))=(sqrt(3*3*3))/sqrt(2*2)$

Take out the squares:

$= \frac{3 \sqrt{3}}{2} or \frac{3}{2} \sqrt{3}$ $=(3sqrt3)/2or 3/2 sqrt3$

How do you simplify sqrt(27/4)√274sqrt(27/4)?