How do you simplify $sqrt(28a^3b^2)$ ?

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Answer 1 · 2016-05-27T14:44:30

$= 2ab sqrt(7a$

$sqrt(28a^3b^2$

Prime factorising $28$ (expressing a number as a product of its prime factors):

$28 = color(green)( 2 * 2 * 7$

$= sqrt( color(green)(2 * 2 * 7) * a^3b^2$

$= sqrt( color(green)(2 ^2 * 7) * color(blue)(a^2) * a * color(blue)( b^2$

$= 2 * color(blue)(a * b) sqrt( color(green)( 7) * a$

$= 2ab sqrt(7a$

How do you simplify sqrt(28a^3b^2)sqrt(28a^3b^2)?