How do you simplify $\sqrt{28 x^{3} y^{4}}$ $sqrt(28x^3y^4)$ ?

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Answer 1 · 2015-09-22T16:34:02

$= 2 x y^{2} \sqrt{7 x}$ $=color(blue)(2xy^2 sqrt (7x$

$\sqrt{28 x^{3} y^{4}}$ $sqrt(28x^3y^4$ can be written as:

$\sqrt{7 \cdot 4 \cdot x^{2} \cdot x \cdot y^{2} \cdot y^{2}}$ $sqrt(7*4*color(blue)(x^2)*x*color(blue)(y^2 *y^2$

$= x y^{2} \sqrt{7 \cdot 2^{2} \cdot x}$ $=xy^2sqrt(7 * 2^2 *x$

$= x y^{2} \cdot 2 \sqrt{7 \cdot x}$ $=xy^2 *2 sqrt (7 *x$

$= 2 x y^{2} \sqrt{7 x}$ $=color(blue)(2xy^2 sqrt (7x$

How do you simplify sqrt(28x^3y^4)√28x3y4sqrt(28x^3y^4)?