How do you simplify $\frac{\sqrt{4}}{36}$ $sqrt(4)/36$ ?

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How do you simplify $\frac{\sqrt{4}}{36}$ $sqrt(4)/36$ ?

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Answer 1 · 2018-04-07T01:43:39

$\frac{1}{18}$ $1/18$

Explanation:

$\frac{\sqrt{4}}{36} = \frac{\sqrt{2^{2}}}{36} = \frac{{(\sqrt{2})}^{2}}{36} = \frac{2}{36} = \frac{1}{18}$ $sqrt4 / 36 = sqrt(2^2) / 36 = (sqrt2)^2 / 36 = 2 / 36 = 1/18$

Answer 2 · 2018-04-07T02:01:57

$\pm \frac{1}{18}$ $+-1/18$

Explanation:

The numerator will simplify to $\pm 2$ $+-2$ , thus we have:

$\pm \frac{2}{36}$ $+-2/36$

We can divide the numerator and denominator by a common factor of $2$ $2$ in order to simplify. We get:

$\pm \frac{1}{18}$ $+-1/18$

as our final answer

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How do you simplify $\frac{\sqrt{4}}{36}$ $sqrt(4)/36$ ?

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