How do you simplify $\sqrt{8 x^{3} y^{2}}$ $sqrt(8x^3y^2)$ ?

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Answer 1 · 2016-04-04T16:54:00

$= 2 x y \sqrt{2 x}$ $= 2 x y sqrt ( 2 x )$

$\sqrt{8 x^{3} y^{2}}$ $sqrt ( 8 x^3 y ^2$

$= \sqrt{2 \cdot 2 \cdot 2 \cdot x \cdot x \cdot x \cdot y \cdot y}$ $=sqrt ( 2 * 2 * 2 * x * x * x * y * y)$

$= \sqrt{2^{2} \cdot 2 \cdot x^{2} \cdot x \cdot y^{2}}$ $=sqrt ( color(blue)(2 ^2) * 2 * color(blue)( x ^2) * x * color(blue)( y^2)$

$= 2 \cdot x \cdot y \sqrt{2 \cdot x}$ $= color(blue)(2 * x * y) sqrt ( 2 * x )$

$= 2 x y \sqrt{2 x}$ $= 2 x y sqrt ( 2 x )$

How do you simplify sqrt(8x^3y^2)√8x3y2sqrt(8x^3y^2)?