How do you simplify $sqrt(972)$ ?

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Answer 1 · 2016-04-24T21:17:29

$18sqrt(3)$

972 ends in 2, therefore is divisible by 2:

$972/2=486$

divisible by 2 again:

$486/2=243$

The sum of digits is multiple of 3, so 243 it is divisble by 3:

$243/3=81$

$81=9xx9=3^4$

so $972=2^2xx3^5$

$sqrt(972)=sqrt(2^2xx3^5)=sqrt(2^2xx3^4xx3)=2xx3^2sqrt(3)=18sqrt(3)$

How do you simplify sqrt(972)sqrt(972)?