How do you simplify $sqrt(9k^4)$ ?

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Answer 1 · 2016-07-09T13:44:02

$sqrt(9k^4)=3k^2$

The given is a radical expression

$sqrt(9k^4)$

$sqrt(3^2*(k^2)^2)$

$sqrt(3^2)*sqrt((k^2)^2)$

$=3k^2$

God bless....I hope the explanation is useful.

Answer 2 · 2016-07-09T13:47:44

$3k^2$

$sqrt(a^b) = (a^b)^(1/2) = a^(b*1/2)$

The square root of $9$ is $3$ .

$sqrt(9k^4)$

$3sqrt(k^4)$

Using the concept from above:

$sqrt(k^4) = (k^4)^(1/2) = k^(4*1/2) = k^(4/2) = k^2$

So:

$3k^2$

How do you simplify sqrt(9k^4)sqrt(9k^4)?