How do you simplify $\sqrt{9 x^{32} y^{28}}$ $sqrt (9x^32y^28)$ ?

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How do you simplify $\sqrt{9 x^{32} y^{28}}$ $sqrt (9x^32y^28)$ ?

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Answer 1 · 2015-07-09T07:06:24

$= 3 x^{16} y^{14}$ $=color(blue)(3 x^16 y ^14$

Explanation:

$\sqrt{9 x^{32} y^{28}}$ $sqrt(9x^32y^28)$

Square root , can also be called as second root , so in terms of fraction, second root is a half power ( $\frac{1}{2}$ $color(blue)(1/2$ )

Rewriting the expression as:
$\sqrt{9 x^{32} y^{28}}$ $sqrt(9x^32y^28)$

$= {(9)}^{\frac{1}{2}} \cdot x^{32 . (\frac{1}{2})} \cdot y^{28 . (\frac{1}{2})}$ $=(9)^(1/2) * x^(32.(1/2)) * y^(28.(1/2))$

$= 3 x^{16} y^{14}$ $=color(blue)(3 x^16 y ^14$

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How do you simplify $\sqrt{9 x^{32} y^{28}}$ $sqrt (9x^32y^28)$ ?

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How do you simplify sqrt (9x^32y^28)√9x32y28sqrt (9x^32y^28)?

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How do you simplify $\sqrt{9 x^{32} y^{28}}$ $sqrt (9x^32y^28)$ ?