How do you simplify $sqrt(b^4c^5)$ ?

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Answer 1 · 2018-03-02T23:35:05

$b^2c^(5/2)$

Recall that $sqrt(x)=x^(1/2).$

Therefore,

$sqrt(b^4c^5)=(b^4c^5)^(1/2)$

Recall that $(xy)^z=x^zy^z$ .

Therefore,

$(b^4c^5)^(1/2)=b^(4*1/2)*c^(5*1/2)=b^2c^(5/2)$

Answer 2 · 2018-03-03T14:15:29

$sqrt(b^4 c^5$ simplifies to $b^2 c^2$ $sqrtc$

Simplify $sqrt(b^4 c^5$

1) Factor into perfect squares as far as possible

$sqrt((b^2)^2 (c^2)^2 (c)$

2) Find the square roots of the perfect squares, but leave the others inside

$b^2 c^2$ $sqrt(c)$ $larr$ answer

How do you simplify sqrt(b^4c^5)sqrt(b^4c^5)?