How do you simplify $\sqrt{{sin}^{2} x cos x} \cdot \sqrt{cos x}$ $sqrt(sin^2xcosx)*sqrtcosx$ ?

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Answer 1 · 2016-11-03T09:28:38

$\frac{1}{2} sin 2 x$ $1/2sin2x$

$\sqrt{{sin}^{2} x cos x} \sqrt{cos x}$ $sqrt(sin^2xcosx)sqrtcosx$

$= \sqrt{{sin}^{2} x cos x cos x}$ $=sqrt(sin^2xcosxcosx)$

$= \sqrt{{sin}^{2} x {cos}^{2} x}$ $=sqrt(sin^2xcos^2x)$

$= sin x cos x$ $=sinxcosx$

$= \frac{1}{2} sin 2 x$ $=1/2sin2x$

How do you simplify sqrt(sin^2xcosx)*sqrtcosx√sin2xcosx⋅√cosxsqrt(sin^2xcosx)*sqrtcosx?