How do you simplify $sqrt (x^4)$ ?

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Answer 1 · 2016-04-04T10:11:25

$+-x^2$

$a^(1/N)$ has N values that are the roots of $a^N=1$

The roots might include complex values that occur in conjugate pairs.

Very briefly, $sqrt1=+-1$ .
$sqrt(x^4) = (x^4)^(1/2)$ has two values $+-x^2$ .
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How do you simplify sqrt (x^4)sqrt (x^4)?