How do you simplify $sqrt128$ ?

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Answer 1 · 2016-02-23T13:06:42

I found: $8sqrt(2)$

I would try by writing $128$ in a different way:

$128=4*4*4*2$

so our root becomes:

$sqrt(4*4*4*2)=sqrt(4)*sqrt(4)*sqrt(4)*sqrt(2)$

we know that $sqrt(4)=2$ , so:

$sqrt(128)=2*2*2*sqrt(2)=8sqrt(2)$

How do you simplify sqrt128 sqrt128?